I could put the Properties file outside the JAR but I like to have a single file with everything inside. The Properties.store() method requires an OutputStream and that's the matter: I have no idea which is the right to choose, since I've had a lot of problems trying to read the Properties file using a FileInputStream.
Hi Jesper, the solution you gave works when i want to read the property file from a class out side the jar.But my problem is there are some classes inside the jar which access my property files.when I add the properties file to jar and use it in another application it is throwing resource not found exception.
To read a Properties file via an Applet: 35. Load a properties file in the startup directory: 36. Have a multi-line value in a properties file: 37. Convert a Properties list into a map. 38. Listing All System Properties: 39. Getting and Setting Properties: 40. Use XML with Properties: 41. Store properties as XML file: 42. Reading and Writing a.
Thanks for the reply. Yes it makes no sense. It's actually the other way around. The EAR file contains multiple JARs, and one of the JAR's contains a environment.properties file, which I do not want. I can of course just delete it, but it needs to be build through Jenkins, so I was hoping for a more intelligent solution, to exclude it during the maven build process.
In the above code we use try with resources so that the output stream gets closed automatically. FileOutputStream(“config.properties”) is used so as to either create a file or use the existing one with the name config.properties. Then we use the Properties class to set the properties into the file.
There are two ways of loading properties files in Java. 1. Using ClassLoader.getResourceAsStream() 2. Using Class.getResourceAsStream() In our example we will use both methods to load a properties file. Following is the content of sample properties file. The properties file will be in package net.viralpatel.resources.
The options and arguments used in this command are: The c option indicates that you want to create a JAR file.; The f option indicates that you want the output to go to a file rather than to stdout.; jar-file is the name that you want the resulting JAR file to have. You can use any filename for a JAR file. By convention, JAR filenames are given a .jar extension, though this is not required.
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Tutorial :Modifying a file inside a jar Unknown 14:01. Unknown. Question: I would like to modify a file inside my jar. Is it possible to do this without extracting and re jarring, from within my application? File i want to modify are configuration files, mostly xml based.
Properties files are a popular mean of configuring applications.Of course Commons Configuration supports this format and enhances significantly the basic java.util.Properties class. This section introduces the features of the PropertiesConfiguration class.Note that PropertiesConfiguration is a very typical example for an implementation of the Configuration interface and many of the features.
That file could thus be located inside the same JAR file as the application loading the properties, or inside another JAR file or directory available on the Java classpath when your Java application is executed. To load properties from a file available on the classpath you need to obtain a Class instance first.
As you can guess from looking at this code, this example shows how to read a resource file from a jar file in a java application, and in this approach, the resource file that I'm reading doesn't have to be in the same directory as the Java class file. As you can imagine, this is a much more flexible approach.
JAR files are packaged with the ZIP file format, so you can use them for tasks such as lossless data compression, archiving, decompression, and archive unpacking. These tasks are among the most common uses of JAR files, and you can realize many JAR file benefits using only these basic features.
Write to properties file inside a java Package. How to write to properties file in a java package using java class in another package.. For example, Java applications are usually packaged up into jar files. The classloader knows how to read resources from a jar file, but the folder structure isn't present on disk.
Hello sir, I have created a jar file having some code in java.What it does is that it calls a shell code (a.sh) which is in the same directory. Now my requirement is that I want to jar the a.sh also along with the other files and want to call the a.sh which is now inside the jar file and not.For configuration purposes, using properties file is a good way of reusing. In this way, when the code is packaged to a jar file, other users can just put the different configurations in the config.properties file. The following is a simple example of using properties file. 1. create the file hierarchy like the following.It's helpful for the jar file manifest to include the main class. The manifest is a special file in a jar located the META-INF directory and named MANIFEST.MF. The manifest file contains special meta information about files within the jar file. Some examples of what we can use a manifest file for include setting the entry point, setting version information and configuring the classpath.